Dear students the factorization of 3x^{2}-8x+5 is (3x-5)(x-1). We have presented the complete solution of this equation with proof.

Let’s see the complete solution:

## Factorization of 3x^{2}-8x+5

First of all we will multiply the first and last number of this equation. As per the equation these numbers are 3 and 5. Multiplication of these two numbers is 3*5=15.

Now we have to make factors of 15 in such a way that the sum of these factors remains 8.

So the factors of 15 are 3 and 5. The sum of 3 and 5 is 8 and the multiplication of 3 & 5 is 15.

Let’s see the solution:

3x^{2}-8x+5 = 0

Let’s take the LHS (Left Hand Side)

3x^{2}-8x+5

= 3x^{2}-3x-5x+5

= 3x(x-1)-5(x-1)

= (3x-5)(x-1)

we know that 3x^{2}-8x+5 = 0

Hence:

(3x-5)(x-1) = 0

x=1 & x=5/3

Answer.

## Factorization of 3×2-8x+5

3x^{2}-8x+5

= 3x^{2} – 3x – 5x + 5

= 3x(x-1)-5(x-1)

= (3x-5)(x-1)

Hence Factorization of 3×2-8x+5 are (3x-5)(x-1).

Also, Read:

Find the zeros of polynomial quadratic x2-2x-8

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