Let's find the zeros of the polynomial p(x)=(x-2)^2-(x+2)^2. p(x) = (x-2)2 - (x+2)2 Note: For solving this we need 2 formuleas as follow: (a+b)2 = a2+b2+2ab(a-b)2 = a2+b2-2ab So we will …

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