We will solve 8×2-22x-21=0 by factorization method. Because it is a quadratic polynomial like ax2+bx+c=0.

## 8×2-22x-21=0 By Factorization Method

8x^{2} – 22x – 21 = 0

for solving this equation first of all we will find the factors of 168 (8*21) in such a way that addition a+b will be -22 and multiplication of a*b will be -168.

Let’s see the factors:

hence two factors are -28 and 6.

8×2-22x-21=0

8x^{2} – 22x – 21 = 0

8x^{2} – 28x + 6x – 21

= 4x(2x – 7) +3(2x – 7)

= (4x + 3)(2x – 7)

Hence the factorization of 8x^{2} – 22x – 21 = (4x + 3)(2x – 7).

Also, Read:

Factorization of 3×2-8x+5

Factorization of x2 -2x -8

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